## When the author observed a sobriety checkpoint conducted by the Dutchess County Sheriff Department, he saw that 676 drivers were screened an

Question

When the author observed a sobriety checkpoint conducted by the Dutchess County Sheriff Department, he saw that 676 drivers were screened and 6 were arrested for dri vi ng while intoxicated. Based on those results, we can estimate that P(I) = 0.00589, where W denotes the event of screening a driver and getting someone who is intoxicated. What does P(I¯) denote, and what is its value?

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2021-10-09T06:17:11+00:00
2021-10-09T06:17:11+00:00 1 Answer
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## Answers ( )

Answer:The probability of drivers who are not intoxicated is P(I¯) and is given as 0.99411.Step-by-step explanation:As the event is indicated as I for the drivers who are intoxicated, the value of I¯ is for the drivers who are not intoxicated. Its value is calculated as follows

P(I¯)=1-P(I)

P(I¯)=1-0.00589

P(I¯)=0.99411

So

the probability of drivers who are not intoxicated is P(I¯) and is given as 0.99411.